A soccer ball is kicked horizontally and rolled off of a 30 meter high cliff. The soccer ball was kicked with a velocity of 17m/s. How long did it take before the ball hit the ground? How far from the cliff did the ball land? (Make sure to include units.) VERTICLE
Acceleration =
Distance =
Initial velocity=
Time=
HORIZONTAL
Distance=
Velocity=
Time=
Show your work when solving for time:

Show your work when solving for horizontal distance:

This will hopefully help. It took me a while so will you mark me brainliest? Thanks!

Explanation:

velocity=Vertical (y) info:

• y = -22.0 m

• viy = 0 m/s

• ay = -9.8 m/s2

distance=

acceleration=

time=

horizontal=Horizontal (x) info:

• x = 35 m

• vix = ?

• ax = 0 m/s2

Initial velocity=16.5 m/s

VOCAB:Horizontal motion is constant

velocity- motion

acceleration-increase in the rate or speed of something.

distance-Distance is a numerical measurement of how far apart objects or points are. In physics or everyday usage, distance may refer to a physical length or an estimation based on other criteria (e.g. "two counties over"). The distance from a point A to a point B is sometimes denoted as. .

time-a point of time as measured in hours and minutes past midnight or noon.

Explanation:

The soccer ball travels a horizontal distance of

33.9 m after being kicked with horizontal velocity of 18.8ms−1. Assuming air resistance is negligible.

Time of flight of the ball

t=Distance Speed=33.918.8s In the vertical direction kinematic equation is

height

h=ut+12gt2 Initial velocity uv=0, acceleration due to gravity g=9.81ms−2. Inserting various values we get h=0×33.918.8+12×9.81×(33.918.8)2⇒h=12×9.81×(33.918.8)2

⇒h=15.9m, rounded to 3 sig. figs

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