A 659 g ball strikes a wall at 15 m/s and rebounds at 11.8 m/s . The ball is in contact with the wall for 0.046 s. What is the magnitude of the average force acting on the ball during the collision? Answer in units of

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

Iwould have to say sorry i can't elaborate more. hope this though!

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