A block is on a surface with µs=0.276. It takes 1.11 N to break it free from static friction. What is the mass of the block?

0.407 kg

Explanation:

Given :

Coefficient of static friction, µs = 0.276

Force, F = 1.1 N

Using the relation :

μ = F/N

N = normal reaction ; N = mg

μ = F / mg

g = acceleration due to gravity = 9.8 m/s²

0.276 = 1.1 / m * 9.8

0.276 = 1.1 / 9.8m

0.276 * 9.8m = 1.1

2.7048m = 1.1

m = 1.1 / 2.7048

m = 0.4066844

Mass = 0.407 kg

3

step-by-step explanation:

10 - 2.8 = 7.2

2 2/5 = 2.4

7.2 / 2.4 = 3

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y