The temperature of 335 g of water changed from 24.5°C to 26.4°C. How much heat did this sample absorb?

3065.4J

Explanation:

Given parameters:

Mass of water  = 335g

Initial temperature  = 24.5°C

Final temperature = 26.4°C

Unknown:

How much heat is absorbed by the sample  = ?

Solution:

To solve this problem, we use the expression below:

    Heat absorbed  = mass x specific heat of water x change in temperature

The specific heat of water  = 4.816J/g°C

So;

 Heat absorbed  = 335 x 4.816 x (26.4  - 24.5)  = 3065.4J

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mass and volume are the answers you are looking for