PLS HELP I NEED A COMPLETE ANSWER AND PROCEDURE FOR THIS, IT'S TIMED A motorcyclist heading east through a small town accelerates at a constant 4.0 m/s² after he leaves the city limits. At time t=0 he is 5.0 m east of the city-limits signpost while he moves east at 15 m/s. Where is he when his speed is 25 m/s?

The motorcyclist is 55 miles east of the small town.

Explanation:

Motion With Constant Acceleration

It's a type of motion where the velocity of an object changes uniformly in time.

The equation that rules the change of velocities is:

Where:

a   = acceleration

vo = initial speed

vf  = final speed

t    = time

The distance traveled by the object is given by:

Using the equation [1] we can solve for a:

Solving [1] for t and substituting into [2] we get the following equation:

The motorcyclist has an acceleration of a=4\ m/s^2 and an initial distance of 5 m where he travels at vo=15 m/s.  It's required to calculate the distance when the speed is vf=25 m/s.

Solving the last equation for X:

Substituting:

X = 50 m

Adding the initial distance:

The motorcyclist is 55 miles east of the small town.

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y

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all three of these explorers explored the midwest and the area around the great lakes, which they subsequently claimed for france.

this was a big portion of territory and expanded new france which before then only consisted of quebec province in northeastern canada