After an initial race George determines that his car loses 35 percent of its acceleration due to air resistance travelling at 38 m/s on flat ground. Assuming that his car travels with a constant acceleration, calculate the maximum speed (Vm), in meters per second, his car can reach on flat ground?\

The maximum velocity of the car at constant acceleration on the road will be 62.2 m/s.

The air resistance is directly proportional to the square of the velocity of an object.

R ∝ v²

The speed of the car was reduced by 35 % at 38 m/s.

So, the speed of the car was reduced by 100% at v' m/s.

The relationship can be given by,

Put the values in the formula and calculate for ,

Therefore, the maximum velocity of the car at constant acceleration on the road will be 62.2 m/s.

Learn more about resistance and speed?

link

64.2 m/s

Explanation:

We are given that

Speed ,v=38 m/s

We have to find the maximum speed when his car reach on flat ground.

Using dimensional analysis

If 35% acceleration reduced by F(res) at 38 m/s

Then, 100% acceleration  can be reduced  by F(res) at v' m/s

Substitute the values

Hence, the maximum speed when his car can reach on flat ground=64.2 m/s

muscle endurance

explanation:

i can do 50 in a row ( but i get so tired after that)

answer: the exterior temperature of commercial jet planes as they leave the stratosphere and return to the ground increases steadily.

explanation:

the lower most layer of atmosphere is troposphere which extends from 0 to 12 km above the surface of the earth. the temperature initially decreases as distance is increased from the earth's surface. commercial jets fly in lower part of the stratosphere. the stratosphere extends upto 50 km. the temperature in stratosphere starts rising again due to presence of ozone which traps the uv rays.

thus, when the planes leave the stratosphere and return to the ground, the exterior temperature increases steadily.