A 1500 kg car traveling to the north is slowed down uniformly from initial velocity of 20 m/s by a 6000 N braking force acting opposite the car's motion. What is the car's velocity after 2.00 s?

12 m/s

Explanation:

Given data

Mass m= 1500kg

intitial velocity u= 20m/s

force F= 6000N

time t= 2 seconds

Required

The final velocity v

From

Ft= mΔv

Ft= m(u-v)

substitute

6000*2= 1500(20-v)

solve for v

12000= 30000- 1500v

collect like terms

12000-30000= -1500v

-18000= -1500v

divide both sides by  -1500v

v= 18000/1500

v=12 m/s

Hence the velccity is 12 m/s

the minimum amperage that the current in this wire would have to have so that its weight is completely supported by the magnetic force due to earth's field, assuming that no other forces except gravity act on it

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.