A dog running at 7.92 m/s slows down to 3.22 m/s in 4.88 s. How far does he go during this period of time?

the distance traveled by the dog is 27.18 m.

Explanation:

Given;

initial velocity of the dog, u = 7.92 m/s

final velocity of the dog, v = 3.22 m/s

time of motion, t = 4.88 s

The distance traveled by the dog is calculated as;

Therefore, the distance traveled by the dog is 27.18 m.

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s