A 540,000 kg plane is coming in to land at 210 m/s. If it hits a 24,000 kg firetruck that's on the runway, inelastically, what will the final velocity be after the collision?

201.06m/s

Explanation:

The solve this problem, we must understand that momentum must be conserved.

This implies that the starting momentum must be the same as the ending momentum. Since we are dealing with an inelastic collision:

      Momentum of Plane  + Momentum of truck  = Momentum of plane + truck

    Mp x Vp  +  Mt x Vt  = V(Mp + Mt)

M is the mass                            

V is the velocity

t is truck

p is the plane

     (540000 x 210) + (24000 x 0)  = V (540000+24000)

            113400000 = 564000V

                  V  = 201.06m/s

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

iron would move it is magnetic there is a mag field around the current in the wire