A gas is enclosed in a cylinder fitted with a light frictionless piston and maintained at atmospheric pressure. When 1400 kcal of heat is added to the gas, the volume is observed to increase slowly from 12.0 m3 to 19.9 m3. a) Calculate the work done by the gas.
I found this to be 7.4 * 10^5 J
b) Calculate the change in internal energy of the gas
J

(a) The work done by the gas 8.005 x 10⁵ J

(b) the change in internal energy is 5.0575 x 10⁶ J

Explanation:

Given;

heat added to the gas, Q = 1400 kcal = 1400 kcal x 4184 J/kcal = 5.858 x 10⁶ J.

change in volume, ΔV = 19.9 m³ - 12.0 m³ = 7.9 m³

atmospheric pressure, P = 101325 N/m²

(a) The work done by the gas = PΔV

                                            = 101325 x 7.9

                                            = 8.005 x 10⁵ J

(b) the change in internal energy is obtained from first law of thermodynamic;

ΔU = Q - W

ΔU = 5.858 x 10⁶ J - 8.005 x 10⁵ J

ΔU = 58.58 x 10⁵J - 8.005 x 10⁵ J

ΔU = 5.0575 x 10⁶ J

answer: d. a cme increases the amount of energy in the solar wind

explanation:

coronal mass ejections, also called cmes, are large clouds of plasma and magnetic field that erupt from the sun. only when the cloud is aimed at earth will the cme hit earth and therefore cause impacts. high-speed solar wind streams come from areas on the sun known as coronal holes.