A 1.00 kg particle has the xy coordinates (-1.20 m, 0.500 m) and a 4.50 kg particle has the xy coordinates (0.600 m, -0.750 m). Both lie on a horizontal plane. At what (a) x and (b) y coordinates must you place a 4.00 kg particle such that the center of mass of the three-particle system has the coordinates (-0.500 m, -0.700 m)

a) The x coordinate of the third mass is -1.562 meters.

b) The y coordinate of the third mass is -0.944 meters.

Explanation:

The center of mass of a system of particles (), measured in meters, is defined by this weighted average:

(1)

Where:

- Mass of the i-th particle, measured in kilograms.

- Location of the i-th particle with respect to origin, measured in meters.

If we know that , , , , and , then the coordinates of the third particle are:

a) The x coordinate of the third mass is -1.562 meters.

b) The y coordinate of the third mass is -0.944 meters.

not too sure thinking all accelerations are pointed down