Three people pull simultaneously on a stubborn donkey. Jack pulls eastward with a force of 83.5 N, Jill pulls with 93.3 N in the northeast direction, and Jane pulls to the southeast with 121 N. (Since the donkey is involved with such uncoordinated people, who can blame it for being stubborn

235.8 N

Explanation:

Given that

Jack

83.5 east

Jill

93.3√2/2 east

93.3√2/2 north

Jane

121√2/2 east

121√2/2 south

From the above listed, we can calculate the total force component on x axis to be

Fx = 83.5 + 93.3√2/2 + 121√2/2

Fx = 83.5 + 65.97 + 85.56

Fx = 235 N (east)

Again, we calculate the total force component on y axis to be

Fy = 93.3√2/2 - 121√2/2

Fy = 65.97 - 85.56

Fy = -19.59 N (south)

Finding the resultant, we have

F = √(Fx²+Fy²)

F = √(235² + (-19.59)²)

F = √55225 + 383.7681

F = √55608.7681

F = 235.8 N

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