A circular disc of 0.67 kg mass and radius of 0.3 m rotates with an angular speed of 8 rad/s. a) Find the moment of inertia of the disc.
b) Calculate the rotational kinetic energy of the disc.

Note: Show the details of your calculations as the final answer alone will not be acceptable.

f is prop to m1xm2 double m1 double force

e/c, where e is its total energy

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft