A rescue pilot drops a survival kit while her plane is flying at an ultitude of 2500m with a forward velocity of 95m. If the air friction is disregarded, how far advance of the starving explorer’s drop zone should she release the package?

Approximately , assuming that .

Explanation:

Let denote the time required for the package to reach the ground. Let and denote the initial and final height of this package.

.

For this package:

Solve for , the time required for the package to reach the ground after being released.

.

.

Assume that the air resistance on this package is negligible. The horizontal ("forward") velocity of this package would be constant (supposedly at .) From calculations above, the package would travel forward at that speed for about . That corresponds to approximately:.

Hence, the package would land approximately in front of where the plane released the package.

step-by-step explanation:

we are given

we have to simplify it

firstly, we will factor it

now, we can cancel like terms

now, we can combine it

so, we get

answer: d. a cme increases the amount of energy in the solar wind

explanation:

coronal mass ejections, also called cmes, are large clouds of plasma and magnetic field that erupt from the sun. only when the cloud is aimed at earth will the cme hit earth and therefore cause impacts. high-speed solar wind streams come from areas on the sun known as coronal holes.