A puppy is running with a speed of 11.2 m/s towards it owner when it gets distracted by a squirrel and stops running. If it halted its run in 2 s,
what is the puppy's acceleration?

-5.6m/s²

Explanation:

Given parameters:

Initial speed  = 11.2m/s

Time of running  = 2s

Unknown:

Acceleration of the puppy  = ?

Solution:

Acceleration is the rate of change of velocity with time.

So;

   Acceleration  =  

final speed  = 0m/s

 Acceleration  =    = -5.6m/s²

higher potential

explanation:

because it is in a high speed so it must move into a of high potential

t = 1/400 h   ⇔ 0.0025 h ⇔ 9s ⇔ 0.15 m

any of the answers are correct.