13.A 10 kg monkey swings on a vine from a point which is 40 m above the jungle floor to a point which is 15 m above the floor. If the monkey was moving at 2 m/s
initially, what will be his speed at the 15 m point?

22.2m/s

Explanation:

Given parameters:

Mass of monkey  = 10kg

Height of descent  = 25m

initial velocity  = 2m/s

Unknown:

Speed at the point which is 15m

Solution:

So to solve this problem, we apply one of the kinematics equation:

        V²  = U²  + 2gH

V is the unknown final speed

U is the initial speed

g is the acceleration due to gravity

H is the height of fall

       V²   = 2² + (2 x 9.8 x 25 ) = 494

       V = 22.2m/s

explanation: in any substance/object, the particles inside it (atoms/molecules) constantly move in random directions and with random speeds (this motion is called brownian motion). as a result, the particles have some kinetic energy (which is proportional to the temperature of the substance).

explanation:

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