If King Kong fell straight down from the top of the Empire State Building (380m high), what is his velocity just before “landing”? a 0.00 m/s
b 86.3 m/s
c -86.3 m/s
d 38.7 m/s

86.3m/s

Explanation:

Given parameters:

Height  = 380m

Unknown:

Final velocity  = ?

Solution:

To solve this problem, we use one of the kinematic equations.

   V²   = U²  + 2gH

V is the final velocity

U is the initial velocity  = 0m/s

g is the acceleration due to gravity

H is the height

           V²   = 0²  +    (2 x 9.8 x 380) = 7448

          V = 86.3m/s

multiple

c. magnitude and direction