Two charges separated by one meter exert a 9 N force on each other. If the charges are pushed to a 3 meter separation, the force on each charge will be 3 N. True or False?

False

Explanation:

The formula of force that exists between two charges is expressed as;

F = kq1q2/r²

If two charges separated by one meter exert a 9 N force on each other, the;

9 = kq1q2/1²

9 = kq1q2 1

If the charges are pushed to a 3 meter separation, then;

F =  kq1q2/3²

F =  kq1q2/9 2

Divide both equations;

9/F = (kq1q2)/ kq1q2/9

9/F =  kq1q2 * 9/ kq1q2

9/F = 9

F = 9/9

F = 1N

Hence if the charges are pushed to a 3 meter separation, then the force on EACH charge will be 1N. Hence the answer is False

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