Please answer the question

Option B. 300 m/s².

Explanation:

From the question given above, the following data were obtained:

Mass (m) of student = 100 Kg

Mass (m) of ball = 1.5 Kg

Force (F) applied on the ball = 450 N

Acceleration (a) of ball =?

From Newton's 2nd law,

F = ma

Where

F => Force applied

m => mass of object

a => acceleration of object.

With the above formula, we can obtain the acceleration of the ball as follow:

Mass (m) of ball = 1.5 Kg

Force (F) applied on the ball = 450 N

Acceleration (a) of ball =?

F = ma

450 = 1.5 × a

Divide both side by 1.5

a = 450 / 1.5

a = 300 m/s²

Therefore, the acceleration of the ball is 300 m/s²

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.