A gas has an initial volume of 24.6 L at a pressure of 1.90 atm and a temperature of 335 K. The pressure of the gas increases to 3.50 atm, and the volume of the gas increases to 31.3 L. What is the final temperature of the gas? 143 K 231 K 485 K 785 K

the final temperature of the gas is 785.18 K

Explanation:

The computation of the final temperature of the gas is shown below:

Here we apply the gas law

= PV ÷ T

Given that

P1 = 1.9 atm

V1 = 24.6 L

T1 = 335 K  

P2 = 3.5 atm

V2 = 31.3 L  

T2 = ?

Now

P1V1 ÷ T1 = P2V2 ÷ T2

(1.9 × 24.6) ÷ 335 = (3.5 × 31.3)/T2

T2 = 785.18 K

hence, the final temperature of the gas is 785.18 K

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