The Starship Enterprise returns from warp drive to ordinary space with a forward speed of 51 km/s . To the crew's great surprise, a Klingon ship is 110 km directly ahead, traveling in the same direction at a mere 30 km/s. Without evasive action, the Enterprise will overtake and collide with the Klingons in just about 5.2 s. The Enterprise's computers react instantly to brake the ship. What magnitude acceleration does the enterprise need to just barely avoid a collision with the klingon ship? Assume the acceleration is constant.

No bc a lot of things r still theories n unproven

Inner peace.. jk it's  a stable electron configuration

Since you have not included the experiment situation and the data, of course, i can not give you specific details about it. but i can you with this question.1) i will assume that the motion is projectile (parabolic) motion.2) yes, the horizontal distance depends on the horizontal velocity as, naming vx the horizontal velocity and t the time, it is: x = vx × t3) now, observe that the flight time depends on the vertical velocity as, naming voy the initial vertical velocity, t the time and y the vertical distance before reaching the ground: y = yo + voy×t - gt² / 2.the higher the initial vertical velocity (voy) the longer the object will be flying and so t will be higher in the equation for the horizontal distance.that explains the relationship between the horizontal distance and the horizontal velocity.

Ithink you got that right thicc queen