Physics, 09.02.2021 02:00 allakhalilpea0zc

A point charge q1 = -8.9 μC is located at the center of a thick conducting shell of inner radius a = 2.8 cm and outer radius b = 4.1 cm, The conducting shell has a net charge of q2 = 2.2 μC. 1)What is Ex(P), the value of the x-component of the electric field at point P, located a distance 8.5 cm along the x-axis from q1?N/C.

2)What is Ey(P), the value of the y-component of the electric field at point P, located a distance 8.5 cm along the x-axis from q1?0N/C.

3)What is Ey(P), the value of the y-component of the electric field at point P, located a distance 8.5 cm along the x-axis from q1?N/C

4)What is Ey(R), the value of the y-component of the electric field at point R, located a distance 1.4 cm along the y-axis from q1?N/C

5)What is σb, the surface charge density at the outer edge of the shell?___C/m2

6)What is σa, the surface charge density at the inner edge of the shell?C/m2

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Answer from: annapittbull12

1) Ex(P) = -8.34602 N/C

2) E_y(P) = -5.23850174216 N/C

3) Question (3) is a similar question to (1)

4) E_y(P) = -5.23850174216 N/C

5) $\sigma _b$ ≈ 1.041466 C/m²

6) σₐ ≈ 2.2330413 C/m²

Explanation:

The given parameter of the point charge located at the center of a conducting shell

The charge of the point charge, q₁ = -8.9 μC

The inner radius of the shell, a = 2.8 cm

The outer radius of the shell, b = 4.1 cm

The charge of the conducting shell, q₂ = 2.2 μC

Therefore, we have;

1) The point P(8.5, 0)

$V = k \cdot \dfrac{q_1 + q_2 }{r^2}$

By plugging in the values, we have;

For

R₁ < R₂ < r, for the electric field at the point, 'P', we have;

$E_x(P) = 9 \times 10^9 \times \dfrac{-8.9 \ \times 10^{-6} + 2.2 \ \times 10 ^{-6} }{(0.085 \ )^2} = -8.34602$

Ex(P) = -8.34602 N/C

2) For the point given with coordinates (8.5, 0), the distance of the y-component of point from the center = 0

The y-component of the electric field = 0 N/C

4) For r = 1.4 cm, along the y-axis we have;

R₁ < r < R₂

Therefore, we have;

$E = k \cdot \left( \dfrac{q_1 }{r} + \dfrac{q_2}{R_2}\right)$

Substituting the values, we get;

$E_y(P) = 9 \times 10^9 \times \left( \dfrac{-8.9 \times 10^{-6}}{0.014} + \dfrac{2.2 \times 10^{-6}}{0.041}\right) = -523850174216$

E_y(P) = -5.23850174216 N/C

5) The charge density, $\sigma _b$ , is given as follows;

$\sigma_b = \dfrac{Q}{A} = \dfrac{2.2 \times 10^{-6} }{4\times \pi \times 0.041^2 } \approx 1.041466 \ C/m^2$

6) Similarly, we have;

$\sigma_a = \dfrac{Q}{A_a} = \dfrac{2.2 \times 10^{-6} }{4\times \pi \times 0.028^2 } \approx 2.2330413 \ C/m^2$

Answer from: Quest

The earths atmosphere is made up of nitrogen and oxygensolids turning into gases is called sublimation.

Answer from: Quest

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia

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