Calculate by how much a spring with spring constant 1.2N/m has been squashed when it has stored 76J,

11.25 m

Explanation:

From the question given above, the following data were obtained:

Spring constant (K) = 1.2 N/m

Energy (E) = 76 J

Compression (e) =?

Energy stored in a spring is given by the following equation:

E = ½Ke²

Where:

E => Energy stored in the spring.

K => spring constant

e => Extention or compression

With the above formula, we can obtain how much the spring has been squashed as follow:

Spring constant (K) = 1.2 N/m

Energy (E) = 76 J

Compression (e) =?

E = ½Ke²

76 = ½ × 1.2 × e²

76 = 0.6 × e²

Divide both side by 0.6

e² = 76 / 0.6

Take the square root of both side.

e = √(76 / 0.6)

e = 11.25 m

Thus, the spring has been squashed by 11.25 m

i think it would be 80 km/h because 30 + 50 = 80 (sorry if this not the right answer i'm trying my best)

c. convergent boundary.

explanation: