Arace car starts from rest and travels east along a straight and level track. for the first 5.0 s of the car's motion, the eastward component of the car's velocity is given by _x(t)=(0.820m/s3)t2.

The solution to your problem is as follows:

a=dv/dt=2*0.82*twhat time velocity is 13.7 solve 13.7=0.82*t^2   t=sqrt(13.7/0.82)  =4.51 sUse the time in the acceleration expression a= 2*0.82*4.51=7.39m/s^2

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