Physics, 29.01.2020 18:00 maryalice2002

Projectile problem: a 7500-kg rocket blasts off vertically from the launch pad with a constant upward acceleration of 2.25 m/s2 and feels no appreciable air resistance. when it has reached a height of 525 m, its engines suddenly fail so that the only force acting on it is now gravity.

a) what is the maximum height this rocket will reach above the launch pad?
b) how much time after engine failure will elapse before the rocket comes crashing down to the launch pad?

Answers: 1

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Answers

Here,

height at failure, h1 = 525 m,
upward acceleration, a = 2.25 m/s^2,
velocity = v m/s,

SO,

v^2 = 2*a*h = 2*2.25*525 = 2362.5
Now, acceleration, g = 9.8 m/s^2,

SO,

heigt, h1 = v^2/2g = 2362.5 / 2*9.8 = 120.54 meters
Hence,

a)
Total height = 525+120.54 = 645.54 meters

b)
time, for h1, t = v/g = sqrt(2362.5)/9.8 = 4.96 sec

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Answer from: mateotrevino1

Height at failure, h1 = 525 m,
upward acceleration, a = 2.25 m/s^2,
velocity = v m/s,

SO,

v^2 = 2*a*h = 2*2.25*525 = 2362.5
Now, acceleration, g = 9.8 m/s^2,

SO,

heigt, h1 = v^2/2g = 2362.5 / 2*9.8 = 120.54 meters
Hence,

a)
Total height = 525+120.54 = 645.54 meters

b)
time, for h1, t = v/g = sqrt(2362.5)/9.8 = 4.96 sec

Answer from: Quest

the answer is kevlar

Answer from: Quest

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.

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