This problem has been solved! See the answer A 6.0 kg object, initially at rest in free space, "explodes" into three segments of equal mass. Two of these segments are observed to be moving with equal speeds of 20 m/s with an angle of 60 degrees between their directions of motion. How much kinetic energy is released in this explosion?

Explanation:

mass of each part = 6 / 3 = 2 kg .

momentum of each of given part = 2 x 20 = 40 kg m/s

Two momentum of 40 kg m/s , acting at angle 60 degree .

Resultant momentum =  2 x 40 cos 30 = 69.28 kg m/s

The third mass will have equal and opposite momentum to this momentum , following law of conservation of momentum .

If its velocity be v .

2 x v = 69.28

v = 34.64 m /s

Third mass will have velocity of 34.64 m /s

Total kinetic energy of all three mass

KE = 1/2 x 2 ( 20² + 20² + 34.64² )

= 400 + 400 + 1199.92

= 1999.93 J .

! 55 !  

write a paragraph or story to explain the transformation between potential and kinetic energy as shown in your picture or model.  

you should have at least 5 complete sentences with a main idea and supporting details.  

you must include the following words:  

potential energy

kinetic energy

mechanical energy

conservation of energy

dude, this is hard lol : ))

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.