Two small charged objects repel each other with a force F when separated by a distance d. If the charge on each object is reduced to 1/ 14 of its original value and the distance between them is reduced to d/ 24 the force becomes Group of answer choices F F * 24 / 196 F * 576 / 14 F * 576 / 196 F * 196 / 576

Ff = F₀ *(576/196)

Explanation:

Assuming that both charges are equal each other, we can express the repulsion force between the charges (assuming that we can treat them as point charges) using Coulomb's Law, as follows:

       

Now, if q reduces to q/14, and d is reduced to d/24, the new value of the force will be:

       

       ⇒

You need to be more specific.  i really don't know what a "motion map" is.you can draw a graph of an object's position, distance, displacement, speed,velocity, or acceleration versus time, or you can draw a graph of the object's x-position versus its y-position and not give any information about time at all.if the graph presents position or displacement against time,  then constant velocity is a straight line . . i.e. a line that has  constant slope.if the graph shows speed against time, then constant velocityis a horizontal piece of line.if the graph shows acceleration against time, then constant  velocity is a piece of line that lies on the x-axis . . it's value is zero. 

Planck decided to assume that atoms could only vibrate at certain frequencies that were whole numbers eg 2f, 3f and so on. others used to think that atoms vibrate continuously