subject
Physics, 12.02.2021 01:00 isabelgarcia188

Millikan measured the electron's charge by observing tiny charged oil drops in an electric field. Each drop had a charge imbalance of only a few electrons. The strength of the electric field was adjusted so that the electric and gravitational forces on a drop would balance and the drop would be suspended in air. In this way the charge on the drop could be calculated. The charge was always found to be a small multiple of 1.6e-19 C. Find the charge on an oil drop weighing 2.27 10-14 N and suspended in a downward field of magnitude 2.36 104 N/C.

ansver
Answers: 1

Another question on Physics

question
Physics, 22.06.2019 13:00
Avoltaic cell converts chemical energy to
Answers: 1
question
Physics, 22.06.2019 13:30
Why do astronauts in the space shuttle weigh less?
Answers: 3
question
Physics, 22.06.2019 14:30
Give one example to show that when substances are mixed,it may result in a chemical or a physical change depending on the conditions.
Answers: 2
question
Physics, 22.06.2019 15:50
An object with initial temperature 130 ∘ f is submerged in large tank of water whose temperature is 50 ∘ f . find a formula for f ( t ) , the temperature of the object after t minutes, if the cooling constant is k = − 0.2 . remember newton's law of cooling (the rate of change of temperature with respect to time is equal to k times the difference between the temperature of the object and the surrounding temperature) ! : )
Answers: 1
You know the right answer?
Millikan measured the electron's charge by observing tiny charged oil drops in an electric field. Ea...
Questions
question
Spanish, 19.04.2020 13:16
question
Mathematics, 19.04.2020 13:16
question
Mathematics, 19.04.2020 13:17
question
Mathematics, 19.04.2020 13:17
Questions on the website: 13722361