A football player is tackled by another player and lands with the combined weight of both players on his knee. If the combined weight of the players is 2400 N and the player's knee measures 0.1 m by 0.1 m, how much pressure is exerted on the turf when the player lands on his knee?

the pressure exerted on the turf when the player lands on his knee is 240,000 N/m².

Explanation:

Given;

combined weight of the players, F = 2400 N

measurement of the player's knee = 0.1 m by 0.1 m

The area of the player's knee is calculated as;

A = 0.1 m x 0.1 m = 0.01 m²

The pressure exerted on the turf when the player lands on his knee is calculated as;

P = F / A

P = (2400 N) / (0.01 m²)

P = 240,000 N/m²

Therefore, the pressure exerted on the turf when the player lands on his knee is 240,000 N/m².

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