Consider two equally charged objects separated by a short distance.  According to Coulomb’s Law, how does doubling the charge on one object affect the electric force present between two charged objects Question 4 options:
A. results in one-half of the original electric force
B. results in one-fourth of the original electric force
C. increases the electric force by a factor of four
D. double force by a factor of four

Coulomb's Law states

F = K Q1 * Q2 / R^2      where K is the force constant

F2 / F1 = 2 Q1 * Q2 / (Q1 * Q2) = 2   where one of the charges is doubled

So the force will be doubled  (D looks rather vague but it cannot be the other three)

where's the following? you gotta add it to know what the choices are

explanation:

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .