A 567-g empty iron kettle is put in a hot stove the kettle absorbs 18,100 j of heat to raise its temperature from 15.0c to a final temperature what is the final temperature? The specific heat capacity of iron is 470j/kg•k

T2 = 355.92 Kelvin or 82.92°C

Explanation:

Given the following data;

Mass = 567g to kilograms = 567/1000 = 0.567 kg

Quantity of heat = 18,100J

Initial temperature = 15°C to Kelvin = 15 + 273 = 288K

Specific heat capacity of iron = 470j/kg•k

To find the final temperature;

Heat capacity is given by the formula;

Where;

Making dt the subject of formula, we have;

Substituting into the equation, we have;

dt = 67.92K

Now, the final temperature T2 is;

But, dt = T2 - T1

T2 = dt + T1

T2 = 67.92 + 288

T2 = 355.92 Kelvin or 82.92°C

depends on what you mean by "group." for order, it would be coleoptera (beetles). for class, it would be insecta (insects). for phylum, it would be the arthropoda (animals with jointed exoskeletons).

explanation: