The height (in centimeters) at time t (in seconds) of a small mass oscillating at the end of a spring is h(t)=5sin(2πt). Estimate its instantaneous velocity at t=3

 h (3) = 0

Explanation:

In this exercise they give us the expression that governs the movement

           h (t) = 5 sin (2πt)

remember that the angles are in radians.

To calculate the instantaneous velocity we substitute

           h (3) = 5 sin (2π 3)

           h (3) = 0

therefore the body this is its position of equilibrium

i think it’s a. this is because if they measured the mass of something with a mass of 150g, then their final answer would have to be approximately 150g. though all of their answers are almost 150, rosa and tran have the closest answers (or the exact answer) to the accurate one.

work: w = fd (given)

work done by chet   =50*1 = 50 j

work done by mika =40*2 = 80 j

work done by sara =30*1.5 = 45 j

work done by bill =60*0.5 = 30 j

students in order from the greatest amount of work done to the least is mika> chet> sara> bill

hence option (b) is correct.