An object accelerates from rest, with a constant acceleration of 14.5 m / s, what will its velocity be after 92 s?

If an object accelerates from rest, with a constant acceleration of 5.4 m/s2, what will its velocity be after 28s? v0 = 0 v= ? a = 5.4 m/s2. ∆x = t = 28 s. 3.

Explanation:

I think 1334

Explanation:

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.