An outfielder throws a baseball to home plate with a velocity of 27 m/s at 35o. It is caught by the first baseman. How long was it in the air

Explanation:

Initial velocity of the ball = 27 m /s .

Its vertical component = 27 sin 35 = 15.48 m /s

Considering vertical displacement to the top point ,

initial velocity u = 15.48 m /s

acceleration due to gravity g = 9.8 ,

velocity at the top v = 0

v = u - gt  

0 = 15.48 - 9.8 t

t = 15.48 / 9.8 = 1.579 s

So time of ascent = 1.579 s

Similarly , time of descent = 1.579

Total time of flight = 2 x 1.579

= 3.16 s

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