A man works on a striaght road from his home to market 2.5km away dwith a speed of 5km/h. Finding the market closed, he instantly truns and walk back home with a speed of 7.5km/h. The average speed of the man over the interval of time 0.40min. Is equal to?

5.625km/h

Explanation:

We are given that

Distance between home and market, d=2.5 km

Speed, v1=5km/h

Speed, v2=7.5 km/h

We have to find the average speed of the man over the interval of time 0 to 40min.

Time,

Using the formula

1 hour =60 min

Distance traveled by man in 10 min with speed 7.5 km/h=

Therefore,

Total distance covered=2.5+2.5/2=3.75 km

Time=40 min=40/60=2/3 hour

Average speed=

Average speed=

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