What is the kinetic energy of a 0.50 KG ball that is traveling at a speed of 40m/s

KE = 1/2 mv2

KE = 1/2 mv2 KE = 1/2 (0.50kg) (40m / s)

KE = 1/2 mv2 KE = 1/2 (0.50kg) (40m / s) 2 KE = 1/2 (0.50) (402)

KE = 1/2 mv2 KE = 1/2 (0.50kg) (40m / s) 2 KE = 1/2 (0.50) (402) KE = 0.5 x 0.50 x 402

KE = 1/2 mv2 KE = 1/2 (0.50kg) (40m / s) 2 KE = 1/2 (0.50) (402) KE = 0.5 x 0.50 x 402 KE = 400 J

KE = 1/2 mv2 KE = 1/2 (0.50kg) (40m / s) 2 KE = 1/2 (0.50) (402) KE = 0.5 x 0.50 x 402 KE = 400 JKE = 0.4 KJ

the minimum amperage that the current in this wire would have to have so that its weight is completely supported by the magnetic force due to earth's field, assuming that no other forces except gravity act on it

i think it would be 5