A 0.38 kg drinking glass is filled with a hot liquid. The liquid transfers 7032 J of energy to the glass. If the temperature of the glass increases by 22 K, what is the specific heat of the glass?

841  J/kg.K

Explanation:

The computation of the specific hear of the glass is shown below:

As we know that

E= cmΔt

where

c denotes specific heat

m denotes 0.38 kg

Δt = temperature = 22k

E denotes energy = 7032 J

Now

7032 J = (0.38) (22) (c)

7032 J = 8.36 (c)

So C = 7032 J ÷ 8.36

= 841  J/kg.K

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