25. This is the most basic pass, used when there is no opponent between you and the receiver. It is sed for quick clean passing over short distance a Chest Pass b. Bounce Pass G. Overhead Pass d. Baseball Pass 26. A basic skill done by moving from one place to another in any direction a Running b. Dribbling o Passing d. Rebounding

27 is the act of continuously bouncing the ball to the floor by one hand or both hands alternately moving to a certain point of the court Running b Dribbling c Passing d. Rebounding 28 quite similar to the seshol it differs in a way the ball is release. It is when the ball is to be

released at the top of the vertical jump Free Throw b. Set Shot Jump Shot 20 is the act of making an attempt to throw the ball to the basket to earn points.

d Lay-up

a Shooting b. Dribbling o. Passing d. Rebounding 30. t the act of transferring the ball positions to a teammate using hand snap b. Dribbling c. Passing d Rebounding

We want to calculate the total metabolic heat generated by a singing canary taking into account heat transfer by radiation, convection and exhaling air. the air temperature is 20 oc, canary’s body internal and surface temperature is 33oc, external body surface convective heat transfer coefficient is 25.2 w/m2 .k, temperature difference between the inhaled and exhaled air is 4.3 oc, the ventilation rate is 0.74 cc of air per second, specific heat of air is 1.0066 kj/kg.k and density of air is 1.16 kg/m3 . assume the canary’s body to be a cylinder with 7 cm diameter and 9 cm length, and heat exchange is from the side as well as the top and bottom of cylinder. calculate 1) the net rate of heat lost by radiation, assuming heat gained by the bird through radiation from the surroundings is 11.5 w; 2) rate of heat transferred by convection to the surrounding air; 3) rate of heat transferred in the exhaling air without considering any internal evaporation; 4) total metabolic power.

Idon’t quite understand this problem

What is the electric force acting between two charges of -0.0045 c and -0.0025 c that are 0.0060 m apart? use fe=kq1q2/r^2 and k = 9.00 x 10^9 n*m^2/c^2 a. 1.7 x 10^7 n b. -1.7 x 10^7 n c. -2.8 x 10^9 n d. 2.8 x 10^9 n