Using Kepler's 3rd law, how long will it take a new planet that is 3.68 x 107 km to travel around the Earth?

Pls mark brainlist...    A graph showing Kepler's 3rd law. ... Kepler's 3rd law is a mathematical formula. It means that if you know the period of a planet's orbit (P = how long it takes the planet to go around the Sun), then you can determine that planet's distance from the Sun (a = the semimajor axis of the planet's orbit).

Explanation:

The square of the orbital period of a planet is proportional to the cube of the semi-major axis of its orbit” That's Kepler's third law. In other words, if you square the 'year' of each planet, and divide it by the cube of its distance to the Sun, you get the same number, for all planets

There are actually three, Kepler's laws that is, of planetary motion: 1) every planet's orbit is an ellipse with the Sun at a focus; 2) a line joining the Sun and a planet sweeps out equal areas in equal times; and 3) the square of a planet's orbital period is proportional to the cube of the semi-major axis of its ..

T=2π√r3GME. For an ellipse, recall that the semi-major axis is one-half the sum of the perihelion and the aphelion.

im srry but ur wrong the answer is d a smooth rock, some red dirt, and an empty bird's nest.

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach