A 0.140 kg clay ball moving at 35 m/s comes to a stop when it hits a wall. The ball strikes the wall and this brings the clay ball to a stop in 0.0080 s. What is the
momentum change experienced by the clay ball? Show the steps on how you
arrived at your final answer.

truck y has a greater velocity than truck x.

a is the best answer your welcome

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y