A 0.150 kg cube of ice (frozen water) is floating in glycerin. The glycerin is in a tall cylinder that has inside radius 5.50 cm. The level of the glycerin is well below the top of the cylinder. Part A If the ice completely melts, by what distance does the height of liquid in the cylinder change

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A 0.150 kg cube fo ice (frozen water) is floating in glycerine. The glycerine is in a tall cylinder that has inside radius 3.10 cm. The level of the glycerine is well below the top of the cylinder.

Part A

If the ice completely melts, by what distance does the height of liquid in the cylinder change? Express your answer with the appropriate units.

Part B

Does the level of liquid rise or fall? That is, is the surface of the water above or below the original level of the glycerine before the ice melted?

Part A: 327 mm

              Part B: Rise

Explanation: When an object is submerged on a fluid, the fluid exerts a upward force on the object called Buoyant Force. It can be calculated by the following relation:

Part A

Because the ice cube is floating on glycerin, its forces are on equilibrium, which means buoyant and weight are equal:

Density of glycerine is 1260 kg/m³.

Volume of a cylinder is

Solving

m

After melted, the volume of a mass of water created is

Density of water is 10³ kg/m³.

1.58 m

The change in heights is

0.327 m

The distance by which the height of liquid in the cylinder change is 327mm.

Part B:

Water has more density than ice. So, when melted, water will take the place of glycerin more than ice and so, liquid will rise on the cylinder.

when earth is in rotational motion around the sun,it displaces from its place.

when a ball is placed on an inclined surface it does both the rotational and circular motion.

explanation:

(75°f − 32) × 5/9 = 23.889°c