Derive an expression for the apparent frequency for the case of a source moving toward a stationary observer

the answer is a)

mark brainliest

prolly a beacuse the momentuem the car has increases while going down hill

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer