A 30-N box is pulled 6.0 m up along a 37° inclined plane. What is the work done by the weight (gravitational force) of the box?

The force due to gravity is called weight. It can be resolved into two axes: along the ramp and normal to the ramp. The ramp angle is 30 degrees so we have

m.g.sin(30) = 25 . 10. 0.5 (parallel) = 125N

and

m.g.cos(30) = 25 . 10 . 0.8660 (normal) = 216.5 N

Work is given by force times distance IN THE DIRECTION OF THE FORCE

so the work due to the parallel gravity force is opposite the direction of the motion; and we signal that with a minus sign: 125 x -3 = -375 joules.

But hang on a durned minute!

Explanation:

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