How much heat in joules is needed to raise the temperature of 9.0 L of water from 0°C to 76.0°C? (Hint: Recall the original definition of the liter.) J

H = m * c * dT

first convert 3,5 to grams which is 3500

1ml equals 1 gram

then find the specific heat for water 4.19

then multiple both by change in temp 70

3500*4.19*70=1026550

bai :>

H = m * c * dT

first convert 3,5 to grams which is 3500

1ml equals 1 gram

then find the specific heat for water 4

a small object of mass 3.66 g and charge -17.6 µc is suspended motionless above the ground when immersed in a uniform electric field perpendicular to the ground. what are the magnitude and direction of the electric field?

the results is a decrease in air temperature with an increase of altitude.

explanation: