Atennis ball is thrown straight up with an initial speed of 22.5 m/s. it is caught at the maximum height of its arc.
a. how high does the ball rise? 25.83 m
b. how long does the ball remain in the air?

To calculate the maximum height, we can use:
2as = v² - u²; where v is 0 at the maximum height, a is -9.81 m/s² and u is 22.5 m/s
2 x -9.81s = -(22.5)²
s = 25.8 m, your answer is correct.

The time of flight of the ball can be given by:
v = u + at; v = 0 at max height
0 = 22.5 - 9.8t
t = 2.30 seconds
It is caught at its maximum height so its time in the air is 2.30 seconds.

The correct answer is c. hope this