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Physics, 03.02.2020 08:53 angiejtc0908

"a bowl of soup at 200á f. is placed in a room of constant temperature of 60á f. the
temperature t of the soup t minutes after it is placed in the room is given by
t(t) = 60 + 140 e
_ 0.075 t
find the temperature of the soup 12 minutes after it is placed in the room. (round to the nearest
degree.)
"

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Answers: 1

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"a bowl of soup at 200á f. is placed in a room of constant temperature of 60á f. the
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