Physics- Static Equilibrium Please show work :( A uniform, horizontal 300 N beam, 5.00 m long, is attached to a wall by a pin connection that allows the beam to rotate. Its far end is supported by a cable that makes an angle of 53.0° with the horizontal. If a 600 N person stands 1.50 m from the wall, find the tension in the cable and the force exerted on the beam by the wall

Given A uniform horizontal beam with a length of 8.00 m and a weight of 200 n is attached to a wall by a pin connection ( allows rotation). Its far end is supported by a cable that makes an angle of 53 degrees with the horizontal. If a 600 n person stands on the beam at 2.00 m from the wall , find the tension in the cable

Now the force acting on the beam are the gravitational force of earth and weight attached to a wall is 200 N which acts at centre. Also force of person standing is 600 N and force exerted is r and tension is T , also torque due to r is zero because it acts at the pivot point. So r = 0

Torque due to tension in the rope is sin 53 x 8.00 x T.

Torque due to force is 2.0 m x 600 N

The weight of beam acts in the centre since the beam is uniform.

So we have

sin 53 x 8.00 x T - 2 m x 600 N - 4 x 200 N = 0

8 .00 x 0.8 x T = 1200 + 800

0.64 T = 2000 N-m

T = 2000 / 0.64

T = 312.5 N

Explanation:

the correct answer is b

are there options? cause you ain’t. real specific