Can you answer these two questions?

a=158 ms^-2 (corr to 3 sigfig)

v=4.16 ms^-1

Explanation:

u=0, v=77.2, s=18.9

v^2=u^2+2as

77.2^2=2(a)(18.9)

a=158 ms^-2

Net force:

F=Wsin(32)=0.5g sin(32)=0.5a

a=g sin(32)

t=0.8

u=0

v=u+at

v=0+gsin(32)(0.8)

v=4.16 ms^-1

answer: good job it's all correct !

explanation:

hi there!

your question asks at which segment does freezing occur.

since we're talking about water, the freezing point of water will be 32 degrees fahrenheit or below.

hope this ! ~