Can you help me plzz ?

We are given:

Mass of the Crate(m) = 71 kg

Applied force(F) = 577 N

Resolving the applied force:

To solve this problem, we will first make a free-body diagram (attached)

The Applied force has been resolved into 2 components denoted by a thinner line and 'g' is the acceleration due to gravity

We found the values by using basic trigonometry

Finding the Normal Force:

Normal force is equal and opposite to the net force applied on the ground. So, we will subtract the vertical component of the applied force from the weight of the crate.

Normal force = mg - F*Sin(27°)

Normal force = [(71)*(9.8)] - [ (577)(0.454) ]                           [g = 9.8 m/s²]

Normal Force = 433.84 N

The answer is frictional force

Velocity=total displacement/timefrom house to store is 500 from store to neighbor is 200 therefore total displacement=500+200=700metrestherefore,700metres/910seconds=0.8metres per second