An object moves with a speed of 30 km/h for 15 minutes and then with a speed of 60km/h for the next 15 minutes. Find the total distance covered by the object.​

Total distance = 22.5 kilometers

Explanation:

Let the first distance be A.

Let the second distance be B

Given the following data;

Speed A = 30km/h

Time A = 15 minutes to hours = 15/60 = 0.25 hour

Speed B = 60km/h

Time B = 15 minutes to hours = 15/60 = 0.25 hour

Now, to find the respective distance traveled;

Distance A = speed A * time A

Distance A = 30 * 0.25

Distance A = 7.5 km

Distance B = speed B * time B

Distance B = 60 * 0.25

Distance B = 15 km

Next, we calculate the total distance traveled;

Total distance = Distance A + distance B

Total distance = 7.5 + 15

Total distance = 22.5 kilometers.

Therefore, the total distance covered by the object is 22.5 kilometers.

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y